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find the transpose of a matrix

You need to enable it. Here is a matrix and its transpose: The superscript "T" means "transpose". For example, given an element a_ij, where i … Required fields are marked *, \(N = \begin{bmatrix} 22 & -21 & -99 \\ 85 & 31 & -2\sqrt{3} \\ 7 & -12 & 57 \end{bmatrix}\), \(N’ = \begin{bmatrix} 22 &85 & 7 \\ -21 & 31 & -12 \\ -99 & -2\sqrt{3} & 57 \end{bmatrix}\), \( \begin{bmatrix} 22 & -21 & -99 \\ 85 & 31 & -2\sqrt{3} \\ 7 & -12 & 57 \end{bmatrix} \), \( \begin{bmatrix} 2 & -3 & 8 \\ 21 & 6 & -6  \\ 4 & -33 & 19 \end{bmatrix} \), \( \begin{bmatrix} 1 & -29 & -8 \\ 2 & 0 & 3 \\ 17 & 15 & 4 \end{bmatrix} \), \( \begin{bmatrix} 2+1 & -3-29 & 8-8 \\ 21+2 & 6+0 & -6+3  \\ 4+17 & -33+15 & 19+4 \end{bmatrix} \), \( \begin{bmatrix} 3 & -32 & 0 \\ 23 & 6 & -3  \\ 21 & -18 & 23 \end{bmatrix} \), \( \begin{bmatrix} 3 & 23 & 21 \\ -32 & 6 & -18  \\ 0 & -3 & 23 \end{bmatrix} \), \( \begin{bmatrix} 2 & 21 & 4 \\ -3 & 6 & -33  \\ 8 & -6 & 19 \end{bmatrix} +  \begin{bmatrix} 1 & 2 & 17 \\ -29 & 0 & 15  \\ -8 & 3 & 4 \end{bmatrix} \), \( \begin{bmatrix} 2 & 8 & 9 \\ 11 & -15 & -13  \end{bmatrix}_{2×3} \), \( k \begin{bmatrix} 2 & 11 \\ 8 & -15 \\ 9 & -13  \end{bmatrix}_{2×3} \), \( \begin{bmatrix} 9 & 8 \\ 2 & -3 \end{bmatrix} \), \( \begin{bmatrix} 4 & 2 \\ 1 & 0 \end{bmatrix} \), \( \begin{bmatrix} 44 & 18 \\ 5 & 4 \end{bmatrix} \Rightarrow (AB)’ = \begin{bmatrix} 44 & 5 \\ 18 & 4 \end{bmatrix} \), \(\begin{bmatrix} 4 & 1 \\ 2 & 0 \end{bmatrix} \begin{bmatrix} 9 & 2 \\ 8 & -3 \end{bmatrix} \), \( \begin{bmatrix} 44 & 5 \\ 18 & 4 \end{bmatrix} \), \(\begin{bmatrix} 9 & 2 \\ 8 & -3 \end{bmatrix} \begin{bmatrix} 4 & 1 \\ 2 & 0 \end{bmatrix} = \begin{bmatrix} 40 & 9 \\ 26 & 8 \end{bmatrix}\). A new matrix is obtained the following way: each [i, j] element of the new matrix gets the value of the [j, i] element of the original one. By, writing another matrix B from A by writing rows of A as columns of B. Consider the matrix If A = || of order m*n then = || of order n*m. So, . Such a matrix is called a Horizontal matrix. What basically happens, is that any element of A, i.e. public class MatrixTransposeExample { public static void main (String args []) { mat[1][0]=2, 2nd iteration for(j=1;j

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